原帖由 <i>濒临O灭绝</i> 于 2012-4-26 16:57:37 发表 <a href="http://www.mscbsc.com/bbs/redirect.php?goto=findpost&pid=4191264&ptid=376552" target="_blank"><img src="http://www.mscbsc.com/bbs/images/common/back.gif" border="0" onload="if(this.width>screen.width*0.7) {this.resized=true; this.width=screen.width*0.7; this.alt='Click here to open new window\nCTRL+Mouse wheel to zoom in/out';}" onmouseover="if(this.width>screen.width*0.7) {this.resized=true; this.width=screen.width*0.7; this.style.cursor='hand'; this.alt='Click here to open new window\nCTRL+Mouse wheel to zoom in/out';}" onclick="if(!this.resized) {return true;} else {window.open(this.src);}" onmousewheel="return imgzoom(this);" alt="" /></a><br />
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是啊，既然在不在激活集内都是干扰，为什么让他加入呢，岂不是浪费了资源（CE,wlash码等）？到底什么原因？是为了能更有效，及时的利用强的导频（如果激活集内有导频变弱，其他的能及时地被利用）？~~~~
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